Which of the following consists of an equal n | vedclass

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(B) In $SO_3$, the sulfur atom is $sp^2$ hybridized. It forms three $S=O$ double bonds. Each double bond consists of one $\sigma$ bond and one $\pi$ b

Vedclass · Accepted Answer

$SO_2$

Vedclass · Answer

(B) In $SO_3$, the sulfur atom is $sp^2$ hybridized. It forms three $S=O$ double bonds. Each double bond consists of one $\sigma$ bond and one $\pi$ bond. The $\pi$ bonds are formed by the overlap of $p$-orbitals of oxygen with $p$ and $d$ orbitals of sulfur. Specifically, $SO_3$ has one $p\pi - p\pi$ bond and two $p\pi - d\pi$ bonds. In $SO_2$, the sulfur atom is $sp^2$ hybridized. It has one lone pair and forms two $S=O$ bonds. One $\pi$ bond is $p\pi - p\pi$ and the other is $p\pi - d\pi$. Thus, $SO_2$ has an equal number ($1$ each) of $p\pi - p\pi$ and $p\pi - d\pi$ bonds. In $CO_2$, there are two $p\pi - p\pi$ bonds and no $p\pi - d\pi$ bonds. In $SO_4^{2-}$, there are two $p\pi - p\pi$ bonds and two $p\pi - d\pi$ bonds, but the question typically refers to neutral molecules like $SO_2$ in this context. Therefore, $SO_2$ is the correct answer.

List-$I$ (Molecule / Species)	List-$II$
$(P)$ $NO_2$ (Unpaired electron in)	$(1)$ Vacant $p$-orbital involved in hybridization
$(Q)$ $B_2H_6$	$(2)$ $sp^2$-orbital
$(R)$ $ClO_3$ (Unpaired electron in)	$(3)$ $sp^3$-orbital
$(S)$ $CH_3^+$	$(4)$ $120^\circ$ Bond angle

Which of the following consists of an equal number of $p\pi - p\pi$ and $p\pi - d\pi$ bonds?

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